Checkin'

[FUNKER]

is this correct

-(pi) + (1 - 2i)((pi)^2) = i^2

i = (-1)^(1/2)
(pi)= 3.142.....

peace
:redface:

[suyver]

No, this is not correct. You are saying that
\pi + (1-2 i)\pi^2=-1
which would imply that
\pi=\left(\mp\frac{1}{10}\pm\frac{i}{5}\right)\lef t(\mp 1+\sqrt{8i-3}\right)
which is clearly not the case...

[matt grime]

Saying pi is transcendental would have saved you all that latexing...

[suyver]

But I like LaTeX'ing! :)

[moshek]

matt:

saying only that pi is transcendental
could make suvey feel more good
with his nice effort to explain the answer.

Moshek
:smile:

[matt grime]

Erm, what the heck does that mean? Perhaps I was offering a tongue in cheek way of pointing out that the answer could be done in far fewer steps, and without making a statement that needs to be checked. Algebraic expressions don't always look like they ought to; I can think of several expressions that appear to have non-zero imaginary part, yet are real.

[moshek]

Matt:

I am still thinking about your question to me if a mathematician is going to the toilet is he also doing mathematics by this.

Until I will have the exact answer for you

you may enjoy to read this:

http://www.physicsforums.com/showthread.php?t=17243

Moshek