Thermal Energy ( Question )

[Kenny09]

1. The problem statement, all variables and given/known data

A copper cube mass of 110g is heated to a temperature of 100 Celcius degrees and then rapidly transferred to a well insulated aluminium can of mass 80g containing 200g of water at 10 C degrees . If the final temperature of the cube and water ( after stirring ) is 14 C .

( c of water and al are 4.2 x 10^3 J/Kg/K and 9.1 x 10^2 J/Kg/K

2. Relevant equations

Calculate the specific heat capacity of the copper . Assuming heat loss to the surrounding is negligible .

3. The attempt at a solution

Heat supplied = heat loss . However i`m struggling with the change in temperature .

[Dick]

The change in temperature of the copper is -86C and the change in the water is +4C?? Is that what you are asking??

[Kenny09]

No i mean about the change of a can .
It should be heat supplied = heat gained isn't it ?
Q of Copper cube = Q of can + Q of Water ?

If can and water are only one object then why would they give us C of aluminum ?

[Dick]

I think you can take the temperature change of the can to be the same as the water it contains.