Heat Conduction - How long does it take?

In summary: However, they will start to feel the effects of hypothermia, and their performance will start to degrade.
  • #1
Fruitbraker
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Homework Statement


In order to stay warm, divers often wear some sort of thermal protection, like a "wetsuit". Often this is a neoprene "foamed" material, which traps gas bubbles as the insulating material. For this problem, assume:

  • the thermal conductivity is that of air (κ = 0.03 W/m-K)
  • the suit thickness is d = 3.5 mm
  • the area of the suit is A ~2 m2
  • the diver's initial body temperature is Td,i = 37°C (98.6°F)
  • the water temperature is Tw = 2°C
  • the diver "weighs" m = 60 kg
  • the specific heat of the diver is cd = 3480 J/kg-K (this is slightly less than the specific heat of water 4184 J/kg-K due to the presence of protein, fat, and minerals)
  • the diver will start to experience loss of motor skills due to hypothermia when his core temperature cools to below Td,f = 35°C (95°F).
    (Note: Throughout this problem we are also implicitly assuming that the diver is at a uniform temperature, which obviously is an over-simplification [since our bodies are evolutionarily engineered to maintain a stable core temperature, even if we have cold limbs...].)
Values I have calculate so far:
Thermal Resistance of wet suit Rth: 0.058333 K/Watt
Heat Capacity of the diver: 208800 J/K
τ: (time constant for differential equation): 12179.9

Estimate how long (in minutes) the diver can stay in the water (before feeling the effects of hypothermia).

Homework Equations



The solution to a differential equation is as follows:

TA(t) = TB + (TA0 - Tb)e^-t/τ

The Attempt at a Solution


[/B]
Solving everything symbolically yields

τln( (TA - TB)/(TA0 - TB)) = -t

TA0 = 37°C
TA = 35°C
TB = 2°C
τ = 12179.9

∴t = 716.673s -> 11.94min

Apparently, the answer is wrong. I even had a friend check my work and he said my work is ok.

What's going on?

Thanks!
 
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  • #2
Simple cross-check: Initial power is 600 W, which won't change much during the process. At 209 kJ/K, a change by 2 K is 418 kJ, and 418kJ/600W = 700 seconds. A bit more because the temperature difference goes down slightly. Your answer is right.

An actual diver won't die after 12 minutes, of course - their body will produce heat, the skin temperature will get lower, limiting heat loss, and so on.
 

1. What is heat conduction?

Heat conduction is the transfer of thermal energy between two objects or regions that are in direct contact with each other. This transfer occurs through the vibration of molecules and the flow of heat from a higher temperature object to a lower temperature object.

2. How does heat conduction work?

Heat conduction works through the transfer of thermal energy from one object to another. This transfer occurs due to the movement of molecules, as particles with more energy (higher temperature) collide with particles with less energy (lower temperature) and transfer their energy. This process continues until both objects reach thermal equilibrium, meaning they have the same temperature.

3. What factors affect the rate of heat conduction?

The rate of heat conduction is affected by several factors including the temperature difference between the two objects, the thermal conductivity of the materials involved, the distance between the objects, and the surface area of contact. A larger temperature difference, higher thermal conductivity, smaller distance, and larger surface area all contribute to a faster rate of heat conduction.

4. How long does it take for heat conduction to occur?

The time it takes for heat conduction to occur depends on several factors such as the temperature difference, the thermal properties of the materials, and the distance between the objects. Generally, heat conduction occurs at a faster rate in materials with high thermal conductivity and with a larger temperature difference. The time it takes for heat conduction to occur can range from a few seconds to several minutes.

5. Can heat conduction be controlled or manipulated?

Yes, heat conduction can be controlled or manipulated through various methods such as using insulating materials to reduce heat transfer, adjusting the temperature difference between the objects, and changing the surface area of contact. This is important in many applications, such as in building insulation and in the design of efficient heating and cooling systems.

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