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TS656577
Feb5-08, 09:15 PM
1. The problem statement, all variables and given/known data

Two horizontal forces act on a 3.5 kg chopping block that can slide over a frictionless kitchen counter, which lies in an xy plane. One force is F1 = (3.1 N) + (7.8 N). Find the acceleration of the chopping block in unit-vector notation when the other force is (a) F2 = (-3.1 N) + (-7.8 N), (b) F2 = (-3.1 N) + (7.8 N), and (c) F2 = (3.1 N) + (-7.8 N).

2. Relevant equations

F=ma?

3. The attempt at a solution

I feel like I want to add vectors but I do not know where the mass comes into play other than in the equation F=ma

catkin
Feb6-08, 01:18 AM
Go with your feeling!

Use vector addition to get a single force on the board then use F = ma (more correctly the vector equation F = ma)

TS656577
Feb6-08, 02:00 PM
So the resulting force for a would be 3.1-3.1 which is 0 and then 7.8-7.8 which is 0. so? the resultant force is 0i+0j. But how would i use this in the F=ma formula

catkin
Feb6-08, 11:40 PM
So the resulting force for a would be 3.1-3.1 which is 0 and then 7.8-7.8 which is 0. so? the resultant force is 0i+0j. But how would i use this in the F=ma formula
Rearrange as
a = F / m
then substitute your resultant force.

andrevdh
Feb7-08, 09:05 AM
So the resulting force for a would be 3.1-3.1 which is 0 and then 7.8-7.8 which is 0. so? the resultant force is 0i+0j. But how would i use this in the F=ma formula

F = ma = mai + maj = 0i + 0j