derivative of metric and log identity

[robousy]

Has anyone seen this identity:

g^{ab}\nabla g_{ab}=\nabla ln|g|

I've seen it used, but want to figure out where it comes from.

Does anyone know a name or have any ideas??

[smallphi]

You will have to show the exact formula. The way it's written, it doesnt make sense - covariant derivative of the metric is zero in GR because the connection is chosen 'metric compatible'.

[robousy]

ok, thanks, I'll check the paper when I get back to my office tomorrow and post.

Rich

[George Jones]

Has anyone seen this identity:

g^{ab}\nabla g_{ab}=\nabla ln|g|

I've seen it used, but want to figure out where it comes from.

Does anyone know a name or have any ideas??

I think you mean

g^{\alpha \beta} \partial_\mu g_{\alpha \beta} = \partial_\mu \ln \left|g\right|.

See pages 12-13 of Poisson.

[robousy]

Thanks Greorge. I Don't have that book but I'll see if I can find someone with it. And thanks for pointing out the correction.

[George Jones]

Lots of have books probably have this, but I won't be able to tell you any others until Monday.

Maybe Carroll.

[samalkhaiat]

[QUOTE]Has anyone seen this identity:

g^{ab}\nabla g_{ab}=\nabla ln|g|

I've seen it used, but want to figure out where it comes from.

Does anyone know a name or have any ideas??

Differentiate the matrix identity

ln[(det.M)] = Tr[(ln M)]

and put

M = g_{\mu \nu}


regards

sam

[robousy]

I'm not seeing it Sam.

\partial_\mu ln|g^{ab}|=\partial_\mu ln[(det.g^{ab})]=\partial_\mu Tr[ln g^{ab} ] =
\partial_\mu (ln g^{00}+lng^{11}+...)

[samalkhaiat]

[QUOTE]I'm not seeing it Sam.

\partial_\mu ln|g^{ab}|=\partial_\mu ln[(det.g^{ab})]=\partial_\mu Tr[ln g^{ab} ] =
\partial_\mu (ln g^{00}+lng^{11}+...)




\partial (ln |G|) = Tr ( \partial ln G) = (G^{-1} \partial G)^{\mu}_{\mu}

thus

\partial (ln|g|) = g^{\mu\nu}\partial g_{\mu\nu}

[robphy]

Thanks Greorge. I Don't have that book but I'll see if I can find someone with it. And thanks for pointing out the correction.

http://books.google.com/books?id=v-Uw_uzbw7EC
search the book for: ln (natural log)

[robousy]

[QUOTE=robousy;1631441]


\partial (ln |G|) = Tr ( \partial ln G) = (G^{-1} \partial G)^{\mu}_{\mu}

thus

\partial (ln|g|) = g^{\mu\nu}\partial g_{\mu\nu}

Great, got it! Thanks a bunch.

[robousy]

http://books.google.com/books?id=v-Uw_uzbw7EC
search the book for: ln (natural log)


Useful link, thanks robphy!