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hi,
let
z=x+iy
z^2=z.zpar=(x+iy)(x-iy)=x^2+y^2
or
z^2=(x+iy)(x+iy)=(x^2-y^2)
Hootenanny
Apr16-08, 10:02 AM
It very much depends on your field. Generally in mathematics when one says the 'square' of a complex number one means literally multiplication by itself as in your latter example. However, physicists working in QM often refer to the multiplication of a complex number by it's complex conjugate as 'squaring' it, as for your former example.
It very much depends on your field. Generally in mathematics when one says the 'square' of a complex number one means literally multiplication by itself as in your latter example. However, physicists working in QM often refer to the multiplication of a complex number by it's complex conjugate as 'squaring' it, as for your former example.
Thank you for you on your response
And on the new information for me
hi,
let
z=x+iy
z^2=z.zpar=(x+iy)(x-iy)=x^2+y^2
or
z^2=(x+iy)(x+iy)=(x^2-y^2)
Take note that (x+iy)(x+iy) is NOT equal to x^2-y^2. It's x^2-y^2+2ixy. Your first 'z^2' is the modulus (size) of the complex number squared. The second is the complex function z*z. They are quite different. A physicist who refers to the first operation as 'squaring' is being pretty sloppy. The proper term is 'modulus squared' and the proper notation is |z|^2.
Hootenanny
Apr16-08, 10:49 AM
Take note that (x+iy)(x+iy) is NOT equal to x^2-y^2. It's x^2-y^2+2ixy.
Nice catch Dick, didn't even see it :redface:
Thank you for you on the note:yuck:
And thank you on the information that you presented
But this is a question in one of the issues:confused:
Thanks
Hootenanny
Apr16-08, 11:27 AM
But this is a question in one of the issues:confused:
Then I would suggest that,
z^2 = x^2 +2ixy - y^2
Then I would suggest that,
z^2 = x^2 +2ixy - y^2
Thank you a lot
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