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m_s_a
Apr16-08, 09:31 AM
hi,








let
z=x+iy

z^2=z.zpar=(x+iy)(x-iy)=x^2+y^2
or
z^2=(x+iy)(x+iy)=(x^2-y^2)

Hootenanny
Apr16-08, 10:02 AM
It very much depends on your field. Generally in mathematics when one says the 'square' of a complex number one means literally multiplication by itself as in your latter example. However, physicists working in QM often refer to the multiplication of a complex number by it's complex conjugate as 'squaring' it, as for your former example.

m_s_a
Apr16-08, 10:19 AM
It very much depends on your field. Generally in mathematics when one says the 'square' of a complex number one means literally multiplication by itself as in your latter example. However, physicists working in QM often refer to the multiplication of a complex number by it's complex conjugate as 'squaring' it, as for your former example.

Thank you for you on your response
And on the new information for me

Dick
Apr16-08, 10:38 AM
hi,








let
z=x+iy

z^2=z.zpar=(x+iy)(x-iy)=x^2+y^2
or
z^2=(x+iy)(x+iy)=(x^2-y^2)

Take note that (x+iy)(x+iy) is NOT equal to x^2-y^2. It's x^2-y^2+2ixy. Your first 'z^2' is the modulus (size) of the complex number squared. The second is the complex function z*z. They are quite different. A physicist who refers to the first operation as 'squaring' is being pretty sloppy. The proper term is 'modulus squared' and the proper notation is |z|^2.

Hootenanny
Apr16-08, 10:49 AM
Take note that (x+iy)(x+iy) is NOT equal to x^2-y^2. It's x^2-y^2+2ixy.
Nice catch Dick, didn't even see it :redface:

m_s_a
Apr16-08, 11:20 AM
Thank you for you on the note:yuck:
And thank you on the information that you presented
But this is a question in one of the issues:confused:
Thanks

Hootenanny
Apr16-08, 11:27 AM
But this is a question in one of the issues:confused:
Then I would suggest that,

z^2 = x^2 +2ixy - y^2

m_s_a
Apr16-08, 12:12 PM
Then I would suggest that,

z^2 = x^2 +2ixy - y^2

Thank you a lot