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mal100
May9-08, 05:54 PM
Hi,

Would anyone be good enough to explain why the 1s2p splitting in a hydrogen atom is 3/4 of the total binding energy?

Would it have anything to do with the Rydberg energy?

E = - 13.6eV/n^2

I appear to have floated through my degree blissfully unaware of electronic configurations and their associated energies. :rolleyes:

Regards,
Malcolm

Redbelly98
May10-08, 12:24 AM
E = - 13.6eV/n^2


That's the key. Use it to calculate the energy difference between the 1S and 2P states.

mal100
May10-08, 03:45 AM
Ok, so

E(1s) = 13.6/1^2 = 13.6
E(2p) = 13.6/2^2 = 3.4

dE = E(1s)-E(2p) = 10.2

dE/E(1s) = 3/4

Thanks!