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looi76
May10-08, 01:04 AM
1. The problem statement, all variables and given/known data
http://img372.imageshack.us/img372/8240/1005200803ki4.png
What are the meter readings in the circuit on the top?

2. Relevant equations
V = IR

3. The attempt at a solution

I = \frac{V}{R}

A_2 = \frac{12}{\frac{20}{75}} = 45A

A_3 = \frac{12}{\frac{30}{75}} = 30A

A_1 = \frac{12}{75} = 0.16A

Are my answers correct?

Defennder
May10-08, 01:33 AM
I don't think your answers are correct. What is 75? Is it supposed to be total equivalence resistance of the circuit? If so, then that means the equivalent resistance of the resistors in parallel is 25 ohms, which is not right. What is the formula to find equivalent resistance of resistors in parallel?