Electric Field of Uniformly Charged Rod

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SUMMARY

The discussion focuses on calculating the electric field strengths generated by a uniformly charged glass rod and a uniformly charged plastic rod, each 10 cm long and charged to +9.00 µC and -9.00 µC, respectively. The rods are positioned 3.90 cm apart, and the electric field strengths are to be determined at distances of 1.0 cm, 2.0 cm, and 3.0 cm from the glass rod. The equation used for calculating the electric field is E = kq/r², where k is Coulomb's constant. Participants emphasize the need to consider the integration method for extended line charges rather than treating them as point charges.

PREREQUISITES
  • Understanding of electric fields and Coulomb's law
  • Familiarity with the concept of uniformly charged rods
  • Knowledge of integration techniques for continuous charge distributions
  • Basic proficiency in physics equations and units
NEXT STEPS
  • Study the electric field of a uniformly charged rod using integration techniques
  • Learn about the superposition principle in electric fields
  • Explore the concept of electric field lines and their representation
  • Review the applications of electric fields in real-world scenarios
USEFUL FOR

Physics students, educators, and anyone interested in understanding electric fields generated by charged objects, particularly in the context of electrostatics and charge distributions.

starrynight24
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Homework Statement


A 10-cm-long thin glass rod uniformly charged to 9.00 and a 10-cm-long thin plastic rod uniformly charged to - 9.00 are placed side by side, 3.90 apart. What are the electric field strengths to at distances 1.0 cm, 2.0 cm, and 3.0 cm from the glass rod along the line connecting the midpoints of the two rods?


Homework Equations



E=kq/r^2

The Attempt at a Solution



I figured out E1. From getting E of left and right and then adding them together. But how do I find E2? or E3?
 
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starrynight24 said:
I figured out E1. From getting E of left and right and then adding them together. But how do I find E2? or E3?

:confused: So you were able to find the field for a distance of 1cm away from the glass rod?

Finding the field at the other two points should be the same process, just with different distance values.
 
starrynight24 said:

Homework Statement


A 10-cm-long thin glass rod uniformly charged to 9.00 and a 10-cm-long thin plastic rod uniformly charged to - 9.00 are placed side by side, 3.90 apart. What are the electric field strengths to at distances 1.0 cm, 2.0 cm, and 3.0 cm from the glass rod along the line connecting the midpoints of the two rods?

Would it be safe to say that the charges are + or - 9.00 microCoulombs? nanoCoulombs? You don't say in your statement. You also don't give the units for the distance separating the rods, but I presume that it's 3.90 centimeters...

Homework Equations



E=kq/r^2

This is the electric field for a point charge, while you are dealing with two extended line segments of charge. Have you already worked out the field of a uniformly charged rod on the perpendicular line extending from the midpoint of the rod? If you don't have the result handy, you will need to set up an integration to solve this problem. (It's not too difficult.)
 

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