Find electric field a distance P from a charged rod

In summary: The correct solution is:In summary, the electric field at point P is 15,000 N/C in the x-direction and 43,301 N/C in the y-direction.
  • #1
isukatphysics69
453
8

Homework Statement


The figure below shows a thin, vertical rod of length L with total charge Q. The indicated point P is a horizontal distance x from the one end of the rod. What is the electric field at point P. Express your answer in component notation in the two blanks below.

L = 5.0 cm, Q = 3.0 nC, and x = 3.0 cm.
physs2.jpg


Homework Equations


kq/r^2

The Attempt at a Solution


theta = arctan(5/3) = 59 deg
total charge = [(8.99x10^9)(3x10^-9)]/((0.03)^2) = 29966
x component = 29966cos59=15417

1.8/2 points
 

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  • #2
Nevermind I just forgot to square the distance lol
 
  • #3
Why am I only getting 1.8/2 points for 15417N/C? is something incorrect?
 
  • #4
this is so frustrating what is the sig figs ??
 
  • #5
LOL IT WAS ROUNDED DOWN TO 15000
 
  • #6
isukatphysics69 said:
LOL IT WAS ROUNDED DOWN TO 15000
So you're good now? :smile:
 
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Likes isukatphysics69
  • #7
berkeman said:
So you're good now? :smile:
yes please see other thread I am stuck again on y component
 
  • #8
isukatphysics69 said:

Homework Statement


The figure below shows a thin, vertical rod of length L with total charge Q. The indicated point P is a horizontal distance x from the one end of the rod. What is the electric field at point P. Express your answer in component notation in the two blanks below.

L = 5.0 cm, Q = 3.0 nC, and x = 3.0 cm.View attachment 230884

Homework Equations


kq/r^2

The Attempt at a Solution


theta = arctan(5/3) = 59 deg
total charge = [(8.99x10^9)(3x10^-9)]/((0.03)^2) = 29966
x component = 29966cos59=15417

1.8/2 points
This working of this problem is incorrect.
 

1. What is the formula for finding the electric field at a distance P from a charged rod?

The formula is E = kQ/P, where E is the electric field strength, k is the Coulomb's constant (9x10^9 Nm^2/C^2), and Q is the charge of the rod.

2. How do you determine the direction of the electric field at a distance P from a charged rod?

The direction of the electric field is determined by the direction of the force that a small positive test charge would experience if placed at that point. If the charge on the rod is positive, the electric field points away from the rod. If the charge is negative, the electric field points towards the rod.

3. Can the electric field strength be negative?

Yes, the electric field strength can be negative if the charge on the rod is negative. This indicates that the force on a positive test charge at that point would be in the opposite direction of the electric field.

4. How does the distance P affect the electric field strength?

The electric field strength is inversely proportional to the distance squared (E ∝ 1/P^2). This means that as the distance from the charged rod increases, the electric field strength decreases.

5. Can the electric field at a distance P from a charged rod be calculated if the rod has a non-uniform charge distribution?

Yes, the electric field can still be calculated using the formula E = kQ/P, as long as the total charge of the rod is known. However, the direction of the electric field may vary depending on the specific charge distribution along the rod.

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