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redshift
May9-04, 11:18 AM
I'd like to make sure I understand it.
It reads...
"Two objects, A and B, are placed in contact with each other on a horizontal, frictionless surface. Object A weighs 1.5kg, and B weighs 2.5kg. If a force of 8.0N is exerted on the surface of object A in contact with B AND on the opposite surface, (1) determine the acceleration of A and B (2) determine the force pushing B."

Do you think this means 8.0N is applied to both objects A and B simultaneously?
(I assume "opposite surface" means the side of A opposite to that contacting B.

arildno
May9-04, 11:30 AM
I feel for you; I think the textbook writer is much too vague:

1)
You write:
I assume "opposite surface" means the side of A opposite to that contacting B

I also have that assumption..

2)
We now come to the heart of the matter:
Does there act a force on B equal to 8.0 N simultaneously with the force(s) acting on A?
This will be true if we ASSUME that the force on A on the contact side, is in fact, generated by B (nothing else makes much sense, I think).
Then, by Newton's 3.law, an equal, and opposite force acts upon B from A.

I believe this is what the problem writer is after..

redshift
May9-04, 11:57 AM
Thanks again. Since the surface is frictionless this is what must be meant.

Parth Dave
May9-04, 06:00 PM
(1) its simply using F = ma, u are given F and m = the sum of the other 2

(2) i think for the second one you have to find the Force via F = ma again, however you have the acceleration and also the mass. not sure tho