Can one use the symmetry of the equation to somehow get the solution faster?
What does such symmetry tell us?
e.g.:
\dot x=y
\dot y=x
is the symmetrical system to the second order DE
\ddot x-x=0
Now we can easily see the solutions (whether e^t or e^(-t)) actually have the same properties as functions. They are even one and the same function, rotated over the y-axis!
So, is the symmetry really providing help or this is just a coincidence?
tiny-tim
Aug6-08, 09:39 AM
… So, is the symmetry really providing help or this is just a coincidence?
Hello Marin! :smile:
Well … if x' = y2
y' = x2
then x'' = 2y y' = 2x2 √x'
so that's a symmetry which is no help at all! :cry:
(I suspect there's a condition that makes it helpful … perhaps something like the Jacobian being unitary … but I'll let someone else answer that! :wink:)
Marin
Aug6-08, 10:39 AM
Hello Marin! :smile:
Well … if x' = y2
y' = x2
then x'' = 2y y' = 2x2 √x'
so that's a symmetry which is no help at all! :cry:
(I suspect there's a condition that makes it helpful … perhaps something like the Jacobian being unitary … but I'll let someone else answer that! :wink:)
Sorry,tiny-tim, couldn't quite get it :(
What's the purpose of "then x'' = 2yy' = 2x2 √x'"
When I look at the system itself, what I see is that what's true for y should be true for x which to my understanding implies that the two functions are somehow similar to one another..
And the big question is, if so, then HOW?
**maybe my question above should be: Does the symmetry of a system of simultaneous DEs provide us somehow to find the solution faster?
tiny-tim
Aug6-08, 07:40 PM
When I look at the system itself, what I see is that what's true for y should be true for x which to my understanding implies that the two functions are somehow similar to one another.
oh I see!
Then, yes, both x and y are solutions to the same equation, so they will be different combinations of the same basic solutions. :smile:
(But I don't see how that would generally help.)
Marin
Aug7-08, 04:38 AM
well, if we could find one solution, e.g.:
dy/dx=x^2 => y=1/3 x^3 +c
it is true then that x=1/3y^3 +c
but if x and y are basically the same functions, do we have?:
1/3 x^3=1/3y^3 +k /.3
x^3=y^3 +c
which I think is the solution to the DE, from which the system has been derived, cuz:
the system was:
dx/dt=y^2
dy/dt=x^2
now dividing the second equation by the first one (to eliminate dt):
dy/dx=x^2/y^2 - which is same with the result above.
Was it just a coincidence or is there some symmetry in it?
EDIT: Sorry, I didn't pay attention I used different variables ( first x and then t)
tiny-tim
Aug7-08, 05:07 AM
Hi Marin! :smile:
dx/dt=y^2
dy/dt=x^2
now dividing the second equation by the first one (to eliminate dt):
dy/dx=x^2/y^2 - which is same with the result above.
Was it just a coincidence or is there some symmetry in it?
Yes, I didn't think of that. :redface:
So long as the right-hand side is a function of only one variable,
we can always divide one equation by the other (as you did):
if dx/dt = f'(y), dy/dt = f'(x), say
then f'(y)dy = f'(x)dx,
so f(y) = f(x) + constant. :smile:
You're right … the symmetry does help! :smile:
Marin
Aug7-08, 07:40 AM
And what about the other cases?
consider the system:
\dot x=x+y^2-2t
\dot y=x^2+y-2t
to be honest, I don't have an idea how to solve it analytically :(
But it's symmetrical... You were talking about the Jacobian hmmm could it be an ansatz here ?
tiny-tim
Aug7-08, 08:35 AM
And what about the other cases?
consider the system:
\dot x=x+y^2-2t
\dot y=x^2+y-2t
to be honest, I don't have an idea how to solve it analytically :(
But it's symmetrical... You were talking about the Jacobian hmmm could it be an ansatz here ?
Sorry, I've no idea.
Just guessing about the Jacobian … someone else wil have to answer that. :redface:
Marin
Aug9-08, 05:19 AM
Does anybody know something about it?
matematikawan
Aug16-08, 05:04 AM
consider the system:
\dot x=x+y^2-2t
\dot y=x^2+y-2t
Hm.... look like a challenging problem. Never seen before. Is there any application for this system?
Look like you all been thinking of reflection symmetry x \leftrightarrow y before. May be we should be looking at other transformation such that system remain invariant. Is Lie symmetry is of any used here ? I don't know.
I will monitor this thread. Hopefully somebody could answered it.
Marin
Aug16-08, 01:57 PM
Well, these systems have no physical meaning (at least are not meant to have here). I am interested in the problem from a pure mathematical point of view.
Look like you all been thinking of reflection symmetry x \leftrightarrow y before - absolutely true - I consider it the most obvious one - if we could find something interesting about it, maybe we could then ask for partial symmetries or negative symmetry, etc.
I know many DEs are not analytically solvable, and many others take a lot of time to find a solution. That's why I'm asking about these symmetrical systems. I think there must be something 'invisible' to us, but hidden in the system.
I would be glad to see every comment or idea - more or less probable :)