given z is complex, sketch the following locus on the Argand diagram:
{(z-3+j)/(z-j) }= square roots of 5
{ }= modulus .
hope anyone can guide .
HallsofIvy
Aug21-08, 07:47 AM
First, you use "i" instead of "j" like a normal human being, not an engineer!:rofl:
"Square" both sides to get
[tex]\frac{(z-3+ i)(\overline{z}-3-i)}{(z+i)(\overline{z}- i)}= 5[/itex]
Setting z= x+ iy that is
[tex](x-2 + i(y+1))(x- 2)- i(y-1)= 5(x+ i(y+1))(x- i(y-1))[/itex]
Multiply that out and separate real and imaginary terms.