wineesarne
Aug21-08, 07:53 AM
Consider f: S1 -> S1: (cos 2 pi x, sin 2 pi x) -> (cos 2 k pi x, sin 2 k pi x).
How to show directly from the homological definition (without using Hurewicz etc) that degree(f) = k?
How to show directly from the homological definition (without using Hurewicz etc) that degree(f) = k?