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wineesarne
Aug21-08, 08:53 AM
Consider f: S1 -> S1: (cos 2 pi x, sin 2 pi x) -> (cos 2 k pi x, sin 2 k pi x).

How to show directly from the homological definition (without using Hurewicz etc) that degree(f) = k?

NoMoreExams
Aug21-08, 10:43 AM
Can you do something like this http://en.wikipedia.org/wiki/Degree_of_a_continuous_mapping#From_a_circle_to_itself