Calculate the displacement of 3 different directions and distances?

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SUMMARY

The discussion focuses on calculating the net displacement from three movements: 130 meters due north, 50 meters due east, and 40 meters due south. The final position is determined by plotting these movements on a Cartesian coordinate system, resulting in the coordinates (100, 90). To find the net displacement from the origin (0,0) to the final position (100, 90), the Pythagorean theorem is applied, yielding a displacement of approximately 126.49 meters.

PREREQUISITES
  • Understanding of Cartesian coordinate systems
  • Basic knowledge of vector addition
  • Familiarity with the Pythagorean theorem
  • Ability to visualize movements on graph paper
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  • Study vector addition and its applications in physics
  • Learn more about the Pythagorean theorem and its use in calculating distances
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This discussion is beneficial for students in physics, educators teaching vector concepts, and anyone interested in understanding displacement calculations in two-dimensional space.

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Can someone please help me understand how to calculate the displacement of 3 different directions and distances?
 
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130m due north, 50m due east, and then 40m due south how can i figure out the net displacement?
 
think of it like on graph paper where the center of the paper is (0,0). if you go straight up 130m you are at (0,130) if you then go straight right 100m you are at (100,130) then if you go left 250m you are at (-150,130). after adding/subtracting all the different movements you find your ending point. Use Pythagorean theorem to find the distance.
 

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