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googlymunja32
Sep10-08, 04:25 PM
kx = x !/r! (x – r)! kx− r

is that right?

mathman
Sep10-08, 04:39 PM
kx = x !/r! (x – r)! kx− r

is that right?

The right side of your equation is confusing. Put in some parentheses.

googlymunja32
Sep10-08, 05:05 PM
see attachment -

mathman
Sep11-08, 04:29 PM
The thunbnail is hard to read. In the second equation there are terms with k to some exponent. It is hard to read these exponents. Also, what is the question - prove the second equation holds?