A question about forces on a mass

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SUMMARY

The discussion focuses on the forces acting on a mass at the lowest point of a curved inclined track. Specifically, it addresses how the normal force on the mass is influenced by its previous acceleration down the track. The key conclusion is that the normal reaction force is affected by the curvature of the track, which introduces a centripetal acceleration that must be considered alongside gravitational acceleration (g). Thus, the normal force differs from that experienced if the mass were simply placed at the bottom of the track.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Knowledge of centripetal acceleration
  • Familiarity with normal force concepts
  • Basic principles of inclined planes and curved tracks
NEXT STEPS
  • Study the effects of curvature on normal force in physics
  • Learn about centripetal acceleration and its applications
  • Explore inclined plane dynamics in detail
  • Investigate the relationship between gravitational force and normal force
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone interested in understanding the dynamics of forces on objects in motion, particularly in curved paths.

lightning208
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The problem gives me a mass at the top of an inclined track. the track is not linear but curved and the bottom of the track is also curved such that mass m will leave the track in a "jump" My question lies, though, in that I want to know the force of the track on mass m when the mass is at the lowest point of the track (so the mass is essentially on a horizontal surface). In other words, the mass has been accelerating down the track and I want to know if this previous acceleration will effect the normal force. Is the normal force the same as if the mass had just been placed at the bottom of the track or is it different because the mass has been sliding down from height h?
 
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lightning208 said:
The problem gives me a mass at the top of an inclined track. the track is not linear but curved and the bottom of the track is also curved such that mass m will leave the track in a "jump" My question lies, though, in that I want to know the force of the track on mass m when the mass is at the lowest point of the track (so the mass is essentially on a horizontal surface). In other words, the mass has been accelerating down the track and I want to know if this previous acceleration will effect the normal force. Is the normal force the same as if the mass had just been placed at the bottom of the track or is it different because the mass has been sliding down from height h?

Hi lightning208! Welcome to PF! :smile:

The normal reaction force will be affected by the slope (which, as you say, is zero in this case), and by the curvature of the track, which causes a centripetal acceleration that has to be "added" to g. :smile:
 
thank you!
 

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