Analysis of Motion in a Medium with Resistance Force: Case I and II

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SUMMARY

The discussion focuses on analyzing the motion of a body projected in a medium with two types of resistance forces: linear resistance (mk*abs(v)) and quadratic resistance (mK*(abs(v))^2). In case I, the motion is bounded, as demonstrated by the derived velocity equation v=Ce^-kt, indicating that the body will eventually stop. In contrast, case II leads to unbounded motion, where the body can theoretically travel infinitely far due to the nature of the quadratic resistance force. The participants clarify the implications of ignoring gravity in this context.

PREREQUISITES
  • Understanding of Newton's second law of motion
  • Familiarity with separation of variables in differential equations
  • Knowledge of linear and quadratic resistance forces
  • Concept of bounded vs. unbounded motion
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  • Study the implications of linear vs. quadratic resistance in motion analysis
  • Learn about the integration of velocity to determine position over time
  • Explore the concept of bounded motion in different physical systems
  • Investigate the effects of ignoring external forces like gravity in motion equations
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Homework Statement



A body of mass is projected with speed and moves under uniform gravity in a medium that exerts a resistance force of magnitude (i) mk*abs(v) or (ii) mK*(abs(v))^2 , where k and K are the positive constants and v is the velocity of the body. Gravity can be ignored. Determine the subsequent motion in each case . Verify motion the motion is bounded in case i , but not in case ii

Homework Equations


F=D+L



The Attempt at a Solution




for case i m*dv/dt= m*k*abs(v)

applying separation of variables, I get

dv/abs(v)=kdt ==> ln(abs(v))=kt ===> v=Ce^-kt or v=Ce^kt , C being a constant and v depending on whether or not is positive or negative.

for case two, my physical system is the quadratic resistance

dv/dt=mk*(abs(v))^2

applying once again the separation of variables method I get:

-1/K*1/v=t ==> v=-1/kt+C

I don't understand how to verify that the body is bounded. I know that a body is bounded if it cannot overcome its gravitational potential energy. I don't understand how I can possibly ignore gravity , unless the body is completely immersed in a vacuum and that cannot be possible if a fluid force is exerting a force on the object.
 
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Benzoate said:
A body of mass is projected with speed and moves under uniform gravity in a medium that exerts a resistance force of magnitude (i) mk*abs(v) or (ii) mK*(abs(v))^2 , where k and K are the positive constants and v is the velocity of the body. Gravity can be ignored. Determine the subsequent motion in each case . Verify motion the motion is bounded in case i , but not in case ii

for case i m*dv/dt= m*k*abs(v)

applying separation of variables, I get

dv/abs(v)=kdt ==> ln(abs(v))=kt ===> v=Ce^-kt or v=Ce^kt , C being a constant and v depending on whether or not is positive or negative.

for case two, my physical system is the quadratic resistance

dv/dt=mk*(abs(v))^2

applying once again the separation of variables method I get:

-1/K*1/v=t ==> v=-1/kt+C

I don't understand how to verify that the body is bounded. I know that a body is bounded if it cannot overcome its gravitational potential energy. I don't understand how I can possibly ignore gravity , unless the body is completely immersed in a vacuum and that cannot be possible if a fluid force is exerting a force on the object.

Hi Benzoate! :smile:

First … big mistake … resistance acceleration is negative, isn't it? :wink:

(otherwise, your method is fine :smile:)

As to gravity, I don't understand why they tell you that the gravity is uniform, and then tell you to ignore it! Well, ignore it anyway! :rolleyes:

"Unbounded" means that the body goes infinitely far (in other words, x(∞) = ∞). To check that, put v = dx/dt, and integrate again to find x(∞). :smile:
 

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