How to Calculate the Electric Field at Point M?

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Homework Help Overview

The discussion revolves around calculating the electric field at a specific point (point M) due to four charges arranged at the corners of a square. The charges include both positive and negative values, and the problem involves understanding the contributions of each charge to the electric field at point M.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to analyze the electric field contributions from each charge, expressing confusion about the cancellation of fields and the application of Gauss' Law. Participants discuss the directions of the electric fields due to the charges and question the assumptions made about their contributions.

Discussion Status

Some participants have provided guidance on the direction of the electric fields and how to combine them, noting that the contributions from the charges should not cancel out as initially thought. There is an ongoing exploration of the calculations and the understanding of electric field units.

Contextual Notes

The original poster mentions that this is an old homework question with no chance of points, indicating a focus on understanding rather than completion for credit. There is also a reference to confusion regarding the units of electric field, specifically the difference between N/C and N.

caz1429
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I've been a reader of this forum last year, but now I've registered and need help understanding electric field.

1. Homework Statement
Four charges q1 = q3 = -q and q2 = q4 = +q, where q = 7 µC, are fixed at the corners of a square with sides a = 1 m.
https://online-s.physics.uiuc.edu/cgi/courses/shell/common/showme.pl?courses/phys212/fall08/homework/01/01/cl10.gif
So 4 charges are on the corners of a square. Top-left and lower-right are -q, and Top-right and lower-left are +q. I need to calculate the x-component of the electric field at the bottom of the square in the middle at point M. The sides of the square are 1m.2. Homework Equations
Gauss' Law3. The Attempt at a Solution
I attempted to draw where the electric field points and it is to the left. When I attempt the problem though everything cancels out and leaves me with zero.

The two bottom charges should cancel out (?) leaving two charges at the top. Pyth. thereom finds the radius to the top two corners sq(1.25)=d

Ex= cos(45)(K)(+Q)/d^2+cos(45)(K)(-q)/d^2 = 0
What am I doing wrong? This is an old homework question with no chance of getting points, but I'm trying to understand it to prepare for an upcoming test. I'm also kind of confused about Gauss' Law. Do you pretend an electron is at the bottom of the square, calculate the force, then divide by q? The answer also asks for N/C while other problems ask for N. Can anyone give me any general units of the electric field? Any help would be appreciated.
1. Homework Statement
 
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caz1429 said:
The two bottom charges should cancel out ...

Not so. Think carefully about the direction of the E field due to:
1. The negative charge that is to the right of the point, and
2. The positive charge that is to the left of the point.
 
The electric field due to the left charge would point right and the field from the right charge would also point right? How would you go about calculating that? When I try to get an answer I always get zero still.
 
caz1429 said:
The electric field due to the left charge would point right and the field from the right charge would also point right? How would you go about calculating that? When I try to get an answer I always get zero still.

Since they both point to the right, just add up the two numbers. The direction will still be to the right.
Since they are both positive numbers, you will not get zero when you add them up.

(Then there's still the two charges at the top to consider...)
 
Thanks a lot for pointing me in the right direction Redbelly98, things finally clicked. Now let's go celebrate a Cubs win!
 
You're welcome! And welcome to PF.
 

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