Thin Rod + Poncual Charge Find Vb-Va

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The discussion focuses on calculating the potential difference Vb - Va between two points A and B in the presence of a thin rod with a linear density of 50 x 10^-9 C/m and a point charge Q of 10 x 10^-9 C. The rod extends from (0m, 4m) to (0m, 14m), while the point charge is located at (-1m, 0m). The participants suggest using the equation Vb - Va = Integral of E * s, where E is derived from the electric field equations E = k|Q|/r^2, and emphasize the need to calculate contributions from both the rod and the point charge separately before summing them.

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Thin Rod + Poncual Charge... Find Vb-Va

Homework Statement


A thin "rod" of 10 m is located between (0m,4m) and (0m,14m). Its linear density is 50*10^-9C/m. Also, there is a ponctal charge of Q=10*10^-9 located at (-1m,0m).
Given 2 points:
A at (0m,-5m)
B at (0m,0m)
Find Vb-Va.

Homework Equations


E=k|Q|/r^2
E*d=V
some integrals...


The Attempt at a Solution


Okay, this seems like a tricky one, does it not?
I know I could use Vb-Va = Integral of : E*s, possibly with s=5
But then, I would have a Vb-Va for the rod, would I have to also calculate the Vb-Va due to the poncyal charge and then sum these 2? This is what I would have done during an exam, though I'm really not sure it'd be good, would it?

Thanks for any help you can provide... believe me, I,ve tried it a couple of times before posting here.:wink:
 
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Ok, so I've tried something, not sure though...
I could separate the question in finding :
-Vb : Vb-from the rog + Vb from the charge
-Va : Va-from the rog + Va from the charge
And then simply substract...is this it? I am not sure but i just think it could...

Thanks for helping
 


I managed to find a number, but as I do not have the answer key, i can't tell if it's good. So if somebody is able to do it, maybe then we could compare our answers :)
this would be really appreciated
 

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