How is the Formula (1+x+x^2+...+x^n^-^2+x^n^-^1)^2 Expanded?

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SUMMARY

The formula (1+x+x^2+...+x^(n-2)+x^(n-1))^2 represents the square of a geometric series. This series can be simplified to (1 - x^(n))/(1 - x). Upon squaring this expression, the result is (1 - x^(n))^2 / (1 - x)^2. This expansion is crucial for understanding the behavior of geometric series in algebraic contexts.

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Pattielli
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Can you tell me what the following formula will be after it gets expanded ?
[tex](1+x+x^2+...+x^n^-^2+x^n^-^1)^2 = ?[/tex]

Thanks a lot,
 
Last edited:
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What's written inside the parantheses is a geometric series. It's equal to (1 - x^(n - 1 + 1)) / (1 - x). Now just square it...
 
Thanks a lot,
 

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