View Full Version : Euler method
Pattielli
May20-04, 08:59 AM
Would you please tell me how to improve Euler's approximation to be better in solving differerential equations ? Can you give me some links to this?
Thank you,
TALewis
May20-04, 12:47 PM
It is literally called the "improved Euler method," the "improved Euler-Cauchy method," or sometimes "Heun's method." It's known as a predictor-corrector method.
I assume you are familiar with the regular Euler method. Recall for Euler's method we are given:
y'=f(x,y)
y(x_0)=y_0
The function f(x,y) tells us the slope of the function at every point, important for 'shooting' from station to station (point to point).
The first step in the improved Euler method is the "predictor" step, and it's identical to the regular Euler method:
y^\ast_{n+1}=y_n+hf(x_n,y_n)
h is the step size. The asterisk denotes the prediction of y_{n+1}. With this prediction, we have two slopes to consider in 'shooting' toward the next station. First is the slope of the current station we used previously:
y'|_n=f(x_n,y_n)
And then the slope at the predicted point:
y'|_{n+1}=f(x_{n+1},y^\ast_{n+1})
We can "correct" our aim by averaging these two slopes and using that as our slope to find the next point:
y_{n+1}=y_n+\frac{1}{2}h[f(x_n,y_n)+f(x_{n+1},y^\ast_{n+1})]
There you have it.
I'm a little slack on differential equations, so perhaps you can shed some light. On the RHS, what's that line?
Pattielli
May21-04, 11:12 AM
Thank you,
Chrono, what is RHS ?
TALewis
May21-04, 11:48 AM
RHS = right hand side
I don't see anything funky on the right hand side. Do you mean this:
y'|_{n+1}
If so, the vertical line doesn't really mean anything other than y' evaluated at n+1. It's a notation quirk I picked, I'm not sure if it's exactly correct.
RHS = right hand side
I don't see anything funky on the right hand side. Do you mean this:
y'|_{n+1}
If so, the vertical line doesn't really mean anything other than y' evaluated at n+1. It's a notation quirk I picked, I'm not sure if it's exactly correct.
That's what I mean. That's the left hand side, isn't it? I don't know what I was thinking when I said that. So would it mean the same without the line there?
TALewis
May21-04, 05:36 PM
The line doesn't really mean anything here. It's just how I chose to say "the slope at this station" and "the slope at the next station." Here's another example of the notation:
\tau_w = \left.\mu\frac{du}{dy}\right|_{y=0}
This, from fluid mechanics, says the shear stress caused by a fluid at a wall (\tau_w) is equal to the fluid's dynamic viscosity (\mu) times the derivative of the fluid velocity parallel to the wall (u) with respect to the perpendicular distance from the wall (y), evaluated at the wall ( y = 0 ).
Pattielli
May22-04, 04:22 AM
I would like to have three other questions.....Please help.
Would you please tell me about Euler and improved Euler methods' applications ?
How can they be in use for what purpose but just solve the differential equations ? An even when they are used for their main purpose, what do people want to learn from their approximations ?
Thank you very much
TALewis
May22-04, 09:51 AM
The Euler and improved Euler can be used to find approximate numerical solutions to differential equations of the form
y'=f(x,y)
where the initiial point of the function is given. That is to say, it is applicable to initial value problems (although it can be applied to boundary value problems through a shooting method). I'm not sure about applications of the method to problems not related to this differential equation.
In practice, we would use a numerical method like the improved Euler method to solve a differential equation where no analytical solution exists. That is to say, there are only a handful of differential equations that can be solved through calculus and algebraic manipulation to give a closed form result.
For example, the field of computational fluid dynamics (CFD) is concerned in part with numerical solutions to the Navier-Stokes equations, which govern fluid flow. The Navier-Stokes equations are a system of nonlinear, second order, partial differential equations with variable coefficients. Here is the NS equation for the x-direction:
\begin{align*}
\rho\left(\frac{\partial u}{\partial t} + u\frac{\partial u}{\partial x} + v\frac{\partial u}{\partial y} + w\frac{\partial u}{\partial z}\right) =\\
-\frac{\partial p}{\partial x} + \rho g_x + \mu\left(\frac{\partial^2 u}{\partial x^2} + \frac{\partial^2 u}{\partial y^2} + \frac{\partial^2 u}{\partial z^2}\right)
\end{align}
There are few analytical solutions to these Navier-Stokes equations. They must be solved by numerical methods in most cases.
In the case of a differential equation that cannot be solved "by hand," the numerical solution produced by method such as Euler's can provide as much information to an engineer as an exact solution. I can plot a numerical solution, numerically differentiate or integrate it, to a degree of numerical precision limited only by my time and computing power.
In practice, however, the Euler and improved Euler are not as accurate as the 4th-order Runge-Kutta method, which is another predictor-corrector "marching" method that's used more often with better results.
arildno
May22-04, 10:52 AM
Just a minor comment here regarding variable coefficients:
Under the assomption of small deformation rates, incompressibility of the fluid, and the validity of Newton's stress/strain rate relationship, it is quite common to express the
stress tensor P as
P=-pI+\mu(\nabla{\vec{v}}+(\nabla{\vec{v}})^{T})
where p is the pressure, \mu the possibly variable dynamic viscosity coefficient, whereas \vec{v} (I is the identity matrix).
In the case of a constant viscosity coefficient, the momentum equation gains the form
indicated by TALewis, in general however, we'll have the force per unit volume terms:
-\nabla{p}+\nabla\cdot(\mu(\nabla{\vec{v}}+(\nabla{ \vec{v}})^{T}))
Pattielli
May22-04, 12:18 PM
Thank you very much, :sm:
vladimir69
May25-04, 12:35 AM
hi
i am studying this stuff at the moment and have some very useful pdf documents explaining this stuff.
let me know if you are interested and i will send you a copy
Pattielli
May25-04, 03:59 AM
Okay, I am waiting for a copy from you
Thank you very much in advance,
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