Why Does S.H.M. Have Two Functions for Displacement?

  • Thread starter Thread starter creativeassault
  • Start date Start date
Click For Summary
SUMMARY

The discussion centers on the two mathematical representations of displacement in simple harmonic motion (S.H.M.): x(t) = A.Sin(wt + phi) and x(t) = A.Cos(wt + phi). Both functions are valid solutions to the differential equation governing S.H.M., with the key distinction being the phase constant "phi," which varies between the sine and cosine forms. This flexibility allows for different initial conditions in the motion of the particle. Understanding this duality is crucial for accurately analyzing velocity and acceleration in S.H.M.

PREREQUISITES
  • Understanding of simple harmonic motion (S.H.M.) principles
  • Familiarity with differential equations
  • Knowledge of trigonometric functions and their properties
  • Basic physics concepts related to motion and forces
NEXT STEPS
  • Study the derivation of the differential equation for simple harmonic motion
  • Explore the relationship between sine and cosine functions in wave mechanics
  • Learn about phase shifts in oscillatory motion
  • Investigate the implications of initial conditions on S.H.M. solutions
USEFUL FOR

Students of physics, educators teaching simple harmonic motion, and anyone interested in the mathematical foundations of oscillatory systems.

creativeassault
Messages
6
Reaction score
0
Hello,
this is my first post on this forum and it is about simple harmonic motion. I can't seem to understand why the displacement x has two functions. What I mean is, x(t)=A.Sin(wt+phi) is the solution of differential equation of s.h.m; which is used by our physics teacher to derive the velocity and acceleration of a particle performing s.h.m; BUT in many textbooks I found that x(t)=A.Cos(wt+phi) ... my question is how can there be two values for x ?

Any help would be very helpfull,
Thank You.
Rohit Arondekar.
 
Physics news on Phys.org
Both versions are perfectly acceptable, as long as you remember that the "phi" in the sine representation will differ from the "phi" in the cosine representation, since we have, in general:
[tex]\cos(\theta-\frac{\pi}{2})=\sin(\theta)[/tex]
 
Yay! cheers arildno :)
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 3 ·
Replies
3
Views
3K
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 8 ·
Replies
8
Views
5K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K