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marlen19861
Nov15-08, 05:59 AM
I need to prove this version of L'Hopitals theorem.

If limf(x)=limg(x)=infinity (as x goes to infinity) then lim[f(x)/g(x)]=lim[f'(x)/g'(x)] (as x goes to infinity)

Any help please?

Thank you

HallsofIvy
Nov15-08, 06:01 AM
Have you tried applying L'Hopital's rule to (1/g(x))/(1/f(x))?