Expectation value problem

[kasse]

1. The problem statement, all variables and given/known data

Calculate \Delta x = \sqrt{\left\langle(x - \left\langle x \right\rangle )^2 \right\rangle} if \left\langle x \right\rangle = 0 and \left\langle x^2 \right\rangle = a^2(\frac{\pi - 6}{12 \pi^2})

2. The attempt at a solution

\left\langle(x - \left\langle x \right\rangle )^2 \right\rangle = \left\langle x^2 - 2x \left\langle x \right\rangle + \left\langle x \right\rangle ^2 \right\rangle

How can I proceed here?

(Also, can sby tell me the name of the markup language I am using?)

[Dick]

Take the expectation value of each of those three terms. You are using TeX.

[HallsofIvy]

1. The problem statement, all variables and given/known data

Calculate \Delta x = \sqrt{\left\langle(x - \left\langle x \right\rangle )^2 \right\rangle} if \left\langle x \right\rangle = 0 and \left\langle x^2 \right\rangle = a^2(\frac{\pi - 6}{12 \pi^2})

2. The attempt at a solution

\left\langle(x - \left\langle x \right\rangle )^2 \right\rangle = \left\langle x^2 - 2x \left\langle x \right\rangle + \left\langle x \right\rangle ^2 \right\rangle

How can I proceed here?

(Also, can sby tell me the name of the markup language I am using?)
You are TOLD that <x>= 0. Put that in and your formula simplifies enormously!

[kasse]

If I could not simplify, could I write \left\langle \left\langle x \right\rangle \right\rangle = \left\langle x \right\rangle ?

[Dick]

<x> is a constant (i.e. not a function). <constant>=constant. Of course those are equal.

[kasse]

Lol. Stupid question.