What Is the Amplitude of Two Interfering Waves?

  • Thread starter Thread starter Niles
  • Start date Start date
  • Tags Tags
    Waves
Click For Summary

Homework Help Overview

The discussion revolves around the concept of amplitude in the context of two interfering waves generated by loudspeakers positioned on the x-axis. The original poster presents a complex expression for the resulting wave and seeks clarification on what constitutes the amplitude within that expression.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the definition of amplitude, questioning whether it refers solely to the constant multiplier or includes other components of the expression. There is a discussion about the role of the cosine term and its relation to the amplitude.

Discussion Status

The conversation is ongoing, with participants offering differing perspectives on the definition of amplitude. Some suggest that the amplitude should encompass everything except the cosine term, while others clarify the role of the cosine in determining the wave's characteristics. No consensus has been reached yet.

Contextual Notes

Participants note the ambiguity in the definition of "amplitude" in physics, indicating that interpretations may vary based on context. The discussion reflects a lack of standardization in terminology related to wave properties.

Niles
Messages
1,834
Reaction score
0

Homework Statement


Hi all.

I have two loudspeakers placed on the x-axis at -L and L respectively. Now I have found the resulting wave at a point z0 on the z-axis. I've used the superposition-principle, and I've arrived at the following expression:

[tex] \widetilde f(\overrightarrow r ,t) = 2A\exp \left[ {i\left( {\frac{{\alpha \left( {\left( {x + y} \right) + \left( {x - y} \right)} \right)}}{2} - \omega t} \right)} \right]\cos \left( {\alpha \frac{{\left( {\left( {x + y} \right) - \left( {x - y} \right)} \right)}}{2}} \right)[/tex]

where the tilde over f indicates that it is complex.

Question: What part of the expression for f is the ampltitude? Is it only 2A, or is it the expontential term and 2A the ampltitude?

Thanks in advance.

Regards,
Niles.
 
Physics news on Phys.org
Niles said:
[tex] \widetilde f(\overrightarrow r ,t) = 2A\exp \left[ {i\left( {\frac{{\alpha \left( {\left( {x + y} \right) + \left( {x - y} \right)} \right)}}{2} - \omega t} \right)} \right]\cos \left( {\alpha \frac{{\left( {\left( {x + y} \right) - \left( {x - y} \right)} \right)}}{2}} \right)[/tex]

Question: What part of the expression for f is the ampltitude? Is it only 2A, or is it the expontential term and 2A the ampltitude?
It depends on what you mean. AFAIK, there is no standard definition of "amplitude", even in physics. You have obviously encountered the term regarding the constant multiplier in front of a sinusoid. And, perhaps you have also encountered it in QM, since you think you might want to include a complext phase? Anyway, it just depends on why you need to know. I would suggest that, since the time-dependence is entirely contained in the exponential, then "the amplitude" may be most suitably identified as everything else besides the complex exponential.
 
Hmm, I would think it is everything besides the cosine, especially because cosine determines the magnitude of the amplitude then.
 
Niles said:
... the magnitude of the amplitude ...
Hmm.
 
Ok, bad way of expressing it. The cosine-term determines when the wave is at it highest positition (i.e. the amplitude).
 
Niles said:
The cosine-term determines when the wave is at it highest positition (i.e. the amplitude).
No. The cosine factor partly determines WHERE (not when; where) the wave will be maximum. The cosine factor doesn't contain any time-dependence. But, anyway, it doesn't matter. You are quite free to call everything besides the cosine factor as the amplitude. That was my main point.
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
10
Views
3K
Replies
9
Views
3K
  • · Replies 36 ·
2
Replies
36
Views
6K
  • · Replies 3 ·
Replies
3
Views
3K
Replies
2
Views
2K
Replies
1
Views
2K
Replies
2
Views
2K
Replies
7
Views
3K