d[x[sup]2[/sup]]/dx = x

[Ursole]

d(x2)/dx = x

PROOF:

d(x2)/dx = d(x + x + x + ....... (x times))/dx

= d[x]/dx + d[x]/dx + d[x]/dx....... (x times)

= 1 + 1 + 1 + ....... (x times)

= x

QED

:wink:

[arildno]

\frac{d}{dx}\sum_{i=1}^{x}x=(\frac{d}{dx}\sum_{i=1 }^{x}1)x+\sum_{i=1}^{x}\frac{dx}{dx}=x+x=2x

[Pattielli]

d(x2)/dx = x

PROOF:

d(x2)/dx = d(x + x + x + ....... (x times))/dx

= d[x]/dx + d[x]/dx + d[x]/dx....... (x times)

= 1 + 1 + 1 + ....... (x times)

= x

QED


What a new invention ! <<:thumbsUp:>>

[gnome]

Isn't this silliness getting old yet?

http://www.physicsforums.com/showthread.php?t=8316