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Random-Hero-
Jan27-09, 11:17 PM
1. The problem statement, all variables and given/known data

I'm really at a loss here, if anyone could help me out I'd really appreciate it.


Given 'a' and 'b' unit vectors,

if |a+b| = root3, determine (2a-5b)dot(b+3a)

Mark44
Jan28-09, 12:24 AM
|a + b|^2 = (a + b)\bullet(a + b)
and |a + b| = sqrt(3) ==> |a + b|^2 = 3

Now, use the fact that the dot product is associative, distributive, and commutative and the two equations above to see if you can evaluate (2a - 5b) )\bullet (b + 3a).

Random-Hero-
Jan28-09, 12:46 AM
well I end up getting 13ab + 6a^2 - 5b^2

The answer is -11/2

I just can't seem to figure out how to get there :s

Mark44
Jan28-09, 01:00 AM
Work with (a + b) \cdot (a + b) = 3. You also know that a and b are unit vectors, which means that a \cdot a = 1 and b \cdot b = 1.

Random-Hero-
Jan28-09, 01:13 AM
Would I do like

(a+b)dot(a+b)=3

1 + 2ab + 1 = 3

ab = 1/2

then sub 1/2 into the ab and then get 6.5 + 6a^2 - 5b^2 and solve from there?

Mark44
Jan28-09, 08:45 AM
Sort of, except that what you show as 6a^2 and -5b^2 is really 6a \cdot a and -5b \cdot b.