Why do horsepower and torque curves crossover around 5252 rpm's?

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Horsepower and torque curves typically crossover around 5252 RPM due to the mathematical relationship between the two, expressed as hp = (tq x rpm)/5252. This crossover point occurs because horsepower is derived from torque, making it a constant in English units. However, the curves may not intersect exactly at this point in practice, and tuning an engine cannot change the fundamental crossover location. The crossover point varies when using different measurement units, such as kilowatts and Newton meters. Understanding this relationship is crucial for interpreting dyno graphs accurately.
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This is more of an automotive question I guess but anyways:

I'm pretty familar with how torque and horsepower are related, the common equation most people think of is hp = ((tq X rpm)/ 5252).

If you look at a lot of dyno graphs, the hp and torque curves always crossover around 5252. Obviously this is because they are equal around 5,252 rpm's. What i don't get is that they do not cross exactly at this point, and another thing I've heard is that some people will tune engines so that they do cross at this point. What is the advantage of this?

here are some example dyno sheets/graphs:

http://www.electricsupercharger.com/images/dyno/DYNO-PORSCHE_84_911_STOCK.jpg

http://dynos.evans-tuning.com/750whpsc300featurecar.jpg
 
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Well, since the horsepower is a calculation based on the torque output, the lines always cross at 5252 rpm. Any graph that shows otherwise is incorrect. You cannot "tune the engine" to change the location of the crossing point.
 
Although the lines cross, the units are not the same. Also the lines only cross at 33000/(2 pi) = 5252.113... when using English units. Using kilowatts and Newton meters, the lines cross at 60,000 / (2 pi) = 9549.296...

Wiki link:

http://en.wikipedia.org/wiki/Torque
 
Here are the equations:
Torque measured in Newton meters. (USE MKS units)

Power (watts) = torque x 2 pi (RPM/60) = torque x RPM/9.549

Power (HP) = watts/746 = torque x RPM/(746 x 9.549) = torque x RPM/7124
 
For simple comparison, I think the same thought process can be followed as a block slides down a hill, - for block down hill, simple starting PE of mgh to final max KE 0.5mv^2 - comparing PE1 to max KE2 would result in finding the work friction did through the process. efficiency is just 100*KE2/PE1. If a mousetrap car travels along a flat surface, a starting PE of 0.5 k th^2 can be measured and maximum velocity of the car can also be measured. If energy efficiency is defined by...

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