Is U-236 to U-235 Decay Possible?

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SUMMARY

The decay of Uranium-236 (U-236) to Uranium-235 (U-235) plus a neutron is not a viable process due to conservation laws. The conservation of mass number and charge is satisfied, but the mass of U-236 exceeds the combined mass of U-235 and a neutron, making the decay energetically unfavorable. In nature, U-236 does not exist stably and is produced artificially through neutron capture by U-235. The primary decay mode for U-236 is alpha decay, resulting in Thorium-232 and an alpha particle.

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  • Nuclear physics fundamentals, including decay processes
  • Understanding of conservation laws in nuclear reactions
  • Knowledge of isotopes and their stability
  • Familiarity with binding energy calculations
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  • Research the mass values of U-236, U-235, and neutron for decay analysis
  • Study the principles of alpha decay and its significance in nuclear physics
  • Explore artificial production methods of U-236 through neutron capture
  • Investigate the chain reaction process involving U-235 and its implications in nuclear reactors
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Determine if decay of U (A-236 Z-92) -> U (A-235 Z-92) + n is possible

mother -> daughter equations for alpha, beta, or gamma

I really don't know where to start. I have a few problems to prove like this but no examples. I understand how to caluclate the binding energy and how much energy is released but I don't understand conservation of energy here. Any suggestions are appreciated.
 
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What is the total energy of the U (A-236 Z-92)
and of
U (A-235 Z-92) + n
calculated in the restframe of each partile, (i.e. their mass)?
 
Dear Someday, I wish I could do some help.

Any candidate process satisfies Conservation of energy, momenta and charge. As for nuclear interactions, there's an extra constraint of conservation of mass number. Obviously, in the candidate process
$$
U(A=236, Z=92) \rightarrow U(A=235, Z=92) + neutron
$$
the charge and mass number conserve. However, to determine whether this process holds natural and automatical, we need the data of their masses. If
$$
mass(U(A=236, Z=92)) > mass(U(A=235, Z=92)) + mass(neutron)
$$
then the interaction is allowed. But I have't the data of U-236, so you have to do it yourself.

However, I guess, the process in forbiden. because, experiment shows that natural decay of U(A=236, Z=92) is the emitting of \alpha particle (nucleu of Helium, A=4, Z=2).
$$
U(A=236, Z=92) \rightarrow Th(A=232, Z=90) + \alpha
$$


1. In nature, U exsists mainly in the form of U-238(99.28%), U-235(0.714%) and U-234(remaining). The three isotopes live together in mineral, and only U-235 is significant in nuclear fissile and atomic bomb. U-236 doesn't exist naturally due to instability, but can be generated via artificial nuclear interactions.

2. A neutron hits a U-235 nucleu and results in a U-236 nucleu. If the energy of the neutron is properly controlled, the U-236 nucleu could fissile into two light nucleus, and emit 2 or 3 daughter neutrons, which will hit U-235 in neighbourhood and repeat the process above again. This is the dubbed Chain Effect. However, averagely, a U-235 has to absorb 1.175 neutrons to break, so a minor portion of the U-236s will not break immediately, and remian in the nuclear waste.
 

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