NayHoMa
Jun1-09, 02:49 AM
Light of frequency 1.21e15 Hz illuminates a piece of tin, and the tin emits photoelectrons of maximum kinetic energy 1.96 eV. What is the threshold frequency of the metal?
Planck's Constant*Frequency = (Planck's Constant)(Threshold Frequency) + Maximum Kinetic Energy
1.21e15 = (6.63e-34)(x) + (1.96eV)
(1.21e15-3.136e-19)/6.63e-34 = X
Answer I got = 1.83e48Hz
might be in the wrong section, I apologize if it is
Planck's Constant*Frequency = (Planck's Constant)(Threshold Frequency) + Maximum Kinetic Energy
1.21e15 = (6.63e-34)(x) + (1.96eV)
(1.21e15-3.136e-19)/6.63e-34 = X
Answer I got = 1.83e48Hz
might be in the wrong section, I apologize if it is