Horizon for Contant Acceleration

[heinz]

Special relativity shows that any accelerated observer
sees an event horizon. In fact, if an observer is accelerated
by a, the horizon is at distance l=c^2/a in the direction
opposite to a.

[Michael_1812]

George,
Heintz says that "if an observer is accelerated by a, the horizon is at distance l=c^2/a in the direction opposite to a."

I am trying to understand this by looking at the picture in the Fermi-Walker section of MTW, and it is not immediately apparent. Where could I look this up?

Many thanks,
Michael

[Naty1]

You can try Wikipedia at
http://en.wikipedia.org/wiki/Event_horizon#Event_horizon_of_an_accelerated_part icle

[George Jones]

George,
Heintz says that "if an observer is accelerated by a, the horizon is at distance l=c^2/a in the direction opposite to a."

I am trying to understand this by looking at the picture in the Fermi-Walker section of MTW, and it is not immediately apparent. Where could I look this up?

Many thanks,
Michael

Do you mean both horizon and horizon distance, or just horizon distance? MTW and I will not have the same spacetime coordinates until tomorrow.