Solving Problem on Capacitor - India IIT Prep

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SUMMARY

The discussion centers on the behavior of a parallel plate capacitor when a dielectric is introduced while it remains isolated and charged. It is established that the force between the plates remains unchanged despite the presence of induced charges on the dielectric. This is because the electric field created by the charge on one plate is independent of distance and the induced charges do not affect the external electric field. The conclusion is that while the dielectric alters the internal field, it does not influence the force between the capacitor plates.

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  • Basic principles of electrostatics
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ambuj123
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Hello
i am new to this forum from India and preparing for IIT
:eek:
well i have question
"If a dielectric is placed between two plates of parallel plate capacitor which is isolated and charged the force between plates decrease or remain same . well i found answer in my book that it remains same but i don't know why?
i think it should be reduced because induced charges appear on the edges of dieelectric and due to these charges two electric field nullify some of the effect?"
Please help
 
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Welcome to PF!

Consider first the capacitor without a dielectric. The charge on one plate creates an electric field which exerts a force on the other plate. That field is proportional to the surface charge density, and is independent of distance. When the dielectric is introduced, induced surface charges do appear on each side of the dielectric, but they cancel. (They effect the field within the dielectric, but not outside it.)
 
Thanks

THANX for help
:smile:
 

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