Two different dielectrics between parallel-plate capacitor

  • #1
zenterix
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Homework Statement
Two dielectrics with dielectric constants ##\kappa_1## and ##\kappa_2## each fill half the space between the plates of a parallel-plate capacitor as shown in the figure below.

Each plate has an area ##A## and the plates are separated by a distance ##d##.

Compute the capacitance of the system.
Relevant Equations
##\oint_S\vec{E}\cdot\hat{n} dS=\frac{Q_{\text{enc}}}{\epsilon_0}##
We have a parallel plate capacitor with two different dielectrics

1706202697499.png


It seems to be the case that the potential difference on each half of the capacitor is the same.

Initially, the electric field was ##\vec{E_0}=\frac{2\sigma_+}{\epsilon_0}\hat{j}##.

If we were to insert a single dielectric material with dielectric constant ##\kappa_e## between the plates, this electric field would weaken to ##\frac{E_0}{\kappa_e}##.

The potential difference would also decrease to ##\frac{|\Delta V_0|}{\kappa_e}##.

But now we have two halves.

If the potential difference is the same in the two halves, then it must be that the electric fields are the same in the two halves. But then the charges on the halves must differ.

Does the reason the potential difference is the same on the two halves arise because of the path independence of ##\vec{E}##?
 
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  • #2
zenterix said:
Does the reason the potential difference is the same on the two halves arise because of the path independence of ##\vec{E}##?
The potential difference is the same for the two halves because of the electrostatic properties of conductors. For any conductor in electrostatic equilibrium, what can you say about the potential at two different points of the conductor?

Suppose you have two conductors that are each in electrostatic equilibrium. What can you say about the potential difference between any point of one conductor and any point of the other conductor? Does it depend on the choice of points?
 
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  • #3
TSny said:
The potential difference is the same for the two halves because of the electrostatic properties of conductors. For any conductor in electrostatic equilibrium, what can you say about the potential at two different points of the conductor?

Suppose you have two conductors that are each in electrostatic equilibrium. What can you say about the potential difference between any point of one conductor and any point of the other conductor? Does it depend on the choice of points?
The potential inside each conductor is constant. Thus, the potential difference between any point inside one conducting plate and any point inside the other conducting plate is constant.

Suppose that instead of conductors we had charged sheets as capacitor plates.

Now what is it that prevents the potential difference from being different in each half of the capacitor?
 
  • #4
If the potential difference is the same......as we've established. Are the two different capacitors in series or parallel?

Also conductors by definition are equipotentials.
 
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  • #5
zenterix said:
The potential inside each conductor is constant. Thus, the potential difference between any point inside one conducting plate and any point inside the other conducting plate is constant.
Yes.

zenterix said:
Suppose that instead of conductors we had charged sheets as capacitor plates.

Now what is it that prevents the potential difference from being different in each half of the capacitor?
If the charge density is fixed on each sheet so that the charge cannot move around on either sheet, then the electric field inside the two dielectrics would be different. So, the potential difference between the sheets would be different for the two halves. We would not call this system a capacitor, since the sheets are not conductors.
 
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  • #6
PhDeezNutz said:
Also conductors by definition are equipotentials.
Not exactly by definition but when conductors are in steady state or electrostatic equilibrium.

In a transient state that is when there is current density inside the conductor that is different from zero then they might not be equipotential even if they are perfect conductors. The case of a perfect conductor that is shaped as a coil and has time varying current density should come up here but I am opening a can of worms now. For anyone who is interested can take a look at this thread https://www.physicsforums.com/threads/inducing-emf-through-a-coil-understanding-flux.940861/.
 
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  • #7
Delta2 said:
Not exactly by definition but when conductors are in steady state or electrostatic equilibrium.

In a transient state that is when there is current density inside the conductor that is different from zero then they might not be equipotential even if they are perfect conductors. The case of a perfect conductor that is shaped as a coil and has time varying current density should come up here but I am opening a can of worms now. For anyone who is interested can take a look at this thread https://www.physicsforums.com/threads/inducing-emf-through-a-coil-understanding-flux.940861/.

I’m still a n00b dealing with electrostatics but your post has given me things to think about as I advanced my studies.

Thanks!
 
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1. How does the presence of two different dielectrics affect the capacitance of a parallel-plate capacitor?

When two different dielectrics are present between the plates of a parallel-plate capacitor, the overall capacitance is determined by the dielectric constants and thicknesses of each dielectric material. The capacitance can be calculated using the formula C = (ε1 * A / d1) + (ε2 * A / d2), where ε1 and ε2 are the dielectric constants, A is the area of the plates, and d1 and d2 are the thicknesses of the dielectric materials.

2. How do you calculate the electric field between the plates of a parallel-plate capacitor with two different dielectrics?

To calculate the electric field between the plates of a parallel-plate capacitor with two different dielectrics, you can use the formula E = V / d_eff, where V is the voltage across the plates and d_eff is the effective distance between the plates. The effective distance can be calculated as d_eff = (d1 * ε1 + d2 * ε2) / (ε1 + ε2), where d1 and d2 are the thicknesses of the dielectric materials and ε1 and ε2 are the dielectric constants.

3. How does the presence of two different dielectrics affect the energy stored in a parallel-plate capacitor?

The energy stored in a parallel-plate capacitor with two different dielectrics is determined by the capacitance and voltage across the plates. The presence of two different dielectrics can affect the overall capacitance of the capacitor, which in turn affects the amount of energy stored. The energy stored in the capacitor can be calculated using the formula U = 0.5 * C * V^2, where U is the energy stored, C is the capacitance, and V is the voltage across the plates.

4. How does the dielectric constant of each material affect the electric field distribution in a parallel-plate capacitor with two different dielectrics?

The dielectric constant of each material affects the electric field distribution in a parallel-plate capacitor with two different dielectrics by influencing how much the electric field is "shielded" by each dielectric. Materials with higher dielectric constants will "shield" the electric field more effectively, leading to a more uniform electric field distribution between the plates. This can result in a more efficient energy storage and discharge process in the capacitor.

5. What are some practical applications of using two different dielectrics in a parallel-plate capacitor?

Some practical applications of using two different dielectrics in a parallel-plate capacitor include increasing the overall capacitance of the capacitor, improving the energy storage efficiency, and

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