View Full Version : A Difficult Equation
Poweranimals
Jul2-04, 04:41 PM
http://ourworld.cs.com/SuperSamuraiStar/math05.jpg
I tried your link. I didn't get any equation, just some fraction. Maybe the link is defective.
Poweranimals
Jul2-04, 04:48 PM
I tried your link. I didn't get any equation, just some fraction. Maybe the link is defective.
Okay, so it is a fraction, but how do I simplify it.
These are the options?
http://ourworld.cs.com/SuperSamuraiStar/math05b.jpg
you want to multiply the numerator by the reciprocal of the denominator.
To do that, begin by writing the number 1 as the ratio of (x - 2) to its self.
That is , writing
1 = (x - 2) / (x - 2) in the first term
and
1 = (x + 2) / (x + 2) in the second term
will help a lot.
Poweranimals
Jul2-04, 05:53 PM
Thanks.
This is a tricky one: http://ourworld.cs.com/SuperSamuraiStar/math15.jpg
fourier jr
Jul2-04, 08:35 PM
Thanks.
This is a tricky one: http://ourworld.cs.com/SuperSamuraiStar/math15.jpg
I got (z^2)/(9x^8)
For the latter one:
Just multiply it by itself, simplify that by collecting coefficients if you can, then put it beneath a one.
You could then simplify or express as a partial fraction as necessary.
vBulletin® v3.8.7, Copyright ©2000-2012, vBulletin Solutions, Inc.