how to find this limit?

[dannysaf]

Limn→∞ (n2/1+5+9+...+(4n-3))

[snipez90]

Since you apparently didn't take VietDao's suggestion, I'll tell you the answer is 1/2 and let you figure out if it's correct or not.

[dannysaf]

I have no idea how to do it...so I am asking to give me a clue to this problem!

[mathman]

The denominator is an arithmetic series, which sums to 2n2 - n. Therefore the limit is 1/2.