Calculate Acceleration Due to Gravity on Moon - 65 Characters

  • Context: Undergrad 
  • Thread starter Thread starter pointintime
  • Start date Start date
  • Tags Tags
    Gravity
Click For Summary
SUMMARY

The discussion focuses on calculating the acceleration due to gravity on the Moon using its radius of 1.74 E 6 meters and mass of 7.35 E 22 kg. The key formula derived is a = G * m_moon / r_moon^2, where G is the gravitational constant. Participants clarify the distinction between net forces acting on different masses, emphasizing that only the mass experiencing the force is relevant in calculations. This understanding is crucial for applying Newton's laws correctly in gravitational contexts.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with gravitational force calculations
  • Knowledge of the gravitational constant (G)
  • Basic algebra for manipulating equations
NEXT STEPS
  • Research the gravitational constant (G) and its value
  • Learn about Newton's law of universal gravitation
  • Explore the concept of net force in different mass systems
  • Study gravitational acceleration calculations on other celestial bodies
USEFUL FOR

Students in physics, educators teaching gravitational concepts, and anyone interested in celestial mechanics and gravitational calculations.

pointintime
Messages
165
Reaction score
0
ok I'll be using a home work problem to ask the question. I'm not asking for help on the question I got the correct answer just need to understand this concept better.

Calculate the acceelration due to gravity on the Moon. The moon's radius is about 1.74 E 6 meters and its mass is 7.35 E 22 kg. For this problem I'll be using m2 as the mass which the moon is orbiting

Ok then...

[tex]\Sigma[/tex]F [in radial direction acting on m2] = (m2 a [radial direction] = Fg = r^-2 G m m2)m2^-1

divide both sides by m2

a [radial direction] = r^-2 G m

I rember in like inclined planes and such when two forces equal and opposite each other are present you can just cancel them out...

so how is there any net force?
how come like in inclined planes when I find the net force i don't include both masses...

Net force = (net mass) a

I don't use net mass in this problem because of why?

Why do I just use m2 and not m1 + m2

net force = (m1 + m2) a
?
 
Physics news on Phys.org
pointintime said:
I rember in like inclined planes and such when two forces equal and opposite each other are present you can just cancel them out...

so how is there any net force?
If I understand what you are asking, it depends on whether the two forces are acting on the same mass or on different masses.

If two equal-and-opposite forces act on the same mass, you may cancel them ... we say that the net force acting on that mass is zero.

However, when the two forces are acting on different masses, they do not cancel. Each mass experiences a net force, due to the one force acting on it. This is the case with the mass and the moon in your calculation.

how come like in inclined planes when I find the net force i don't include both masses...

Net force = (net mass) a

I don't use net mass in this problem because of why?

The equation, Fnet = ma, refers to the net (vector sum) of only the forces that act on the mass m. Any other masses, or forces acting on masses other than m, are irrelevant here.
 
Newton's gravitational law: Force = G m_moon m_object / r_moon ^2

You just pull the mass of the object out of the expression, and put it to the side:
Force = [ G m_moon / r_moon ^2 ] m_object

acceleration of object = F / m_object = the stuff in the brackets
 

Similar threads

Replies
23
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 33 ·
2
Replies
33
Views
6K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 33 ·
2
Replies
33
Views
3K
  • · Replies 8 ·
Replies
8
Views
4K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 20 ·
Replies
20
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K