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Would there be any observable difference between these two cases: A) two "ordinary" black holes merge. B) one of the two merging black holes is derived from anti-matter? Thanks for any thoughts.
Dmitry67
Sep24-09, 12:39 PM
There should be no difference.
1. Black holes do not have 'solid surface'
2. When any matter approaches singularity inside the horizon, it becomes a subject of so heavy tidal forces/hawking emission from apparent horizons/heating that the difference between matter and antimatter dissapears (like it was at some point of history soon after the Big bang)
Jonathan Scott
Sep24-09, 01:24 PM
Would there be any observable difference between these two cases: A) two "ordinary" black holes merge. B) one of the two merging black holes is derived from anti-matter? Thanks for any thoughts.
According to the "no hair" theorem, the only externally observable properties of a standard classical black hole are mass (rest energy), electric charge and angular momentum, so there is no observable distinction between one made of matter and one made of antimatter.
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