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noob314
Sep29-09, 10:04 PM
I need help on this one



\int_0^{100} \sqrt{x}ln{x}dx



I've tried integrating it by parts and ended up with the equation

[(2/3)(x^3/2)(lnx) - (4/9)(x^3/2)] from 0 to 100

However, I can't plug it in because there's no value of ln(0). So, I'm at a loss right now. Any idea on where to go from here?

Bohrok
Sep29-09, 11:44 PM
x^{\frac{3}{2}}\ln x = x^{\frac{1}{2}}(x\ln x)

Let ~u = \frac{1}{x}. ~~Then ~\lim_{x\rightarrow0}(x\ln x) = \lim_{u\rightarrow+\infty}\frac{\ln\frac{1}{u}}{u}

Or you might try xlnx = ln(xx) and use the limit of xx as x→0+

lanedance
Sep29-09, 11:49 PM
i think the integral is not well defined and you should be considering

\stackrel{lim}{a \rightarrow 0} \int_a^{100} dx.\sqrt{x}.ln(x)

noob314
Sep30-09, 12:12 AM
x^{\frac{3}{2}}\ln x = x^{\frac{1}{2}}(x\ln x)

Let ~u = \frac{1}{x}. ~~Then ~\lim_{x\rightarrow0}(x\ln x) = \lim_{u\rightarrow+\infty}\frac{\ln\frac{1}{u}}{u}

Or you might try xlnx = ln(xx) and use the limit of xx as x→0+

Thanks. That really helped.