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If x+2y=2 and (x+y)2=9, what is the value of y?
And the answer is not -1.. what is the trick here that I'm missing? The answer is supposed to be 5.
If x+2y=2 and (x+y)2=9, what is the value of y?
And the answer is not -1.. what is the trick here that I'm missing? The answer is supposed to be 5.
x+2y=2
so
x=2-2y
so
(x+y)^2=(2-2y+y)^2=(2-y)^2=9
square root of both sides:
\pm (2-y)=3
-3=2-y or 3=2-y
So the solutions (note the plural) are:
(-8,5) and (4,-1)
I'm guessing you forgot that every number has two square roots. ;)
ahhh see? these little simple things.. thanks NateTG!
I should be doing other things at 2 in the morning :grumpy:
fourier jr
Jul10-04, 01:13 AM
monique is a cutie :blush:
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