Differential Equation

[fan_103]

x^2d^2y/dx^2+3xdy/dx+5y=3x


I don't know where to start with the question ,can anyone here help me plzz.

[pbandjay]

This equation looks to be solvable using the variation of parameters method or a green's function. To rearrange:

y''+3x^{-1}y'+5x^{-2}y=3x^{-1}

The method states that if you have

y''+a_1(x)y'+a_2(x)y=F

then let y1 and y2 be solutions to the associated homogeneous equation.

Then the particular solution is

y_p=u_1y_1+u_2y_2

where u1 and u2 satisfy both:

y_1u_1'+y_2u_2'=0

y_1'u_1'+y_2'u_2'=F

and the general solution:

y(x)=c_1y_1+c_2y_2+y_p

To use a green's function to find yp, then

y_p(x)=\displaystyle\int_{x_0}^xK(x,t)F(t)dt

where the green's function, K(x,t), is defined as

K(x,t)=\frac{y_1(t)y_2(x)-y_2(t)y_1(x)}{W[y_1,y_2](t)}

and the Wronskian, W[y1,y2](t), is defined as

W[y_1,y_2](t)=\begin{vmatrix} y_1 & y_2 \\ y_1' & y_2' \end{vmatrix}=y_1y_2'-y_2y_1'

unless I made a typo somewhere.

[fan_103]

Wow U r legend!Thanks a lot matey ;)