View Full Version : Calculating radius from volume
bluffreggie
Oct21-09, 09:00 AM
Hi all,
i am working through some worked examples for my course and there seems to be a step missing.
the step says
"the internal diameter of the vessel can be determined from"
V=PI*r^2*4r
Now all im given is that the volume V is 20 litres. is there any way i can determine the radius from this?
The answer written is r=0.117m
Thanks for any help guys!!
scottie_000
Oct21-09, 09:09 AM
Assuming the vessel is filled with water, do you know how many litres of water is in a cubic metre? Or how many ml makes up a cubic centimetre?
From there you need to be able to rearrange this equation to solve for r in terms of V
SinghTutorial
Oct21-09, 09:09 AM
if I say x^3 = 8, is it ok to say x = 2
This problem is just like the one above
V = PI * 4 * r^3
or r^3 = V / ( PI * 4)
so r = ( V / (PI * 4) )^(1/3)
Another this to remember is V is given in liters so you have to convert it into m^3.
20 liters = .02 m^3
and if you plug the above equation in a calculator, you get r = 0.11675m
hope it helps
scottie_000
Oct21-09, 09:13 AM
Or you could just answer the entire question....
Is it not better to give a few hints, so that the OP will understand how to do it themselves?
bluffreggie
Oct21-09, 09:25 AM
Ahh i forgot the like terms of the r^2 and r!!!!
i can not seem to get it to work on my calculator.
I get for (V/Pi*4)) = 0.02/Pi*4 = 1.59*10-3
How do i use ^(1/3)?
Is it the abc function?
scottie_000
Oct21-09, 09:35 AM
^(1/3) just means cube root, so is there a button with a 3 in a square root sign?
bluffreggie
Oct21-09, 09:39 AM
yeah got it just. thanks mate. That was just the front end of the question. the rest is straight forward just got hung up on the rearrangment side of it. i was close but not close enough!!!!
scottie_000
Oct21-09, 10:38 AM
Glad to help
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