Moles of excess

[Jules18]

1. The problem statement, all variables and given/known data

2 N2O + 3 O2 = 4 NO2

If 6 moles of N2O and 8 moles of O2 react to produce as much NO2 as possible, how many moles of which reactant will remain at the end of the reaction?

3. The attempt at a solution

I got an answer, but I don't want to sway anyone so I won't say what it was. I just want to check my answer with someone else's o:) o:)

[Bohrok]

The limiting reactant should be the 8 moles of O2.

The way I learned to find out which number of moles is limiting is to divide each number of moles of reactant by the coefficient of the reactant in the balanced equation. The one with the smallest number is the limiting reactant.

[Jules18]

i know, right?? that's what I thought but the answer key says the excess is supposed to be O2.
that's why I posted this - i'm pretty sure it's wrong but I needed a second opinion

[Borek]

I got an answer, but I don't want to sway anyone so I won't say what it was.

You may safely give your answers, we are not that easy to confuse. But we are easily doubting someone who says so really did anything - way too often lazy students try to play that trick.

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[Jules18]

I'm not a lazy student!!! How dare you, good sir.

[Jules18]

You may safely give your answers, we are not that easy to confuse. But we are easily doubting someone who says so really did anything - way too often lazy students try to play that trick.

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You sir, are a douche.

lol anyways it's fine, Bohrok's answer was enough of a reassurance.

You should trust students on here a little more. Most of the lazy ones don't even bother to look for help. I really, really hate being called lazy, it's a thing.

[Borek]

I have not said YOU are the lazy student. I wrote that we often see people stating "I did it" when they have not. We see it so often we don't believe even when it is a just truth.

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