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staka
Oct21-09, 09:22 PM
How may I solve for the normal of a direction vector?

If, for example, the direction vector is (1,2,-2), then what is its normal.

Moo Of Doom
Oct22-09, 02:55 AM
Any normal vector (x, y, z) satisfies (x, y, z).(1, 2, -2) = 0, so you just have to solve the linear equation x + 2y - 2z = 0.

HallsofIvy
Oct22-09, 07:08 AM
The plane x+2y- 2z= 0 is normal to that given vector. Any vector in that plane will be normal to the vector.

staka
Oct22-09, 07:52 PM
Ok. Got it, thanks.