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if air is made up of only 2gases oxygen and nitrogen, and the molecular mass of air is 29g/mol, find the % of each component in the air,
what i thought i should do is make 2 equations,
Mw(O)=16
Mw(N)=14
X*16 + Y*14 = 29 (in 1mol of air)
X + Y = 1
but the solution to this is not possible, i get one as a negative pct
the correct answer is meant to be
72.5%
27.5%
PhaseShifter
Oct23-09, 05:23 AM
Mw(O)=16
Mw(N)=14
These are atomic weights, not molecular weights.
Remember oxygen and nitrogen are both diatomic gases.
thanks, so my equations would go
X*2*16 + Y*2*14 = 29 (in 1mol of air)
X + Y = 1
then i get 75%, 25%
is this correct? the "correct" answer in my book is 72.5% 27.5%
PhaseShifter
Oct23-09, 05:44 AM
Is that 72.5% by weight, or by number of molecules?
it actually doesnt say, never thought of that,
is what i got by mol;ecules? how would i make the conversioin
got it,,
0.75*28=21g
0.25*32=8g
8/29=27.6%
21/29=72.4%
close enough
25% and 75% is a correct answer using 28, 32 and 29 as molar masses and assuming final result must be just molar fraction.
27.6% and 72.4% is a correct answer in terms of mass percentage.
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