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Shackleford
Nov18-09, 12:07 PM
http://i111.photobucket.com/albums/n149/camarolt4z28/a.jpg
http://i111.photobucket.com/albums/n149/camarolt4z28/b.jpg

% change E = .0022 - (-.0022) = .0044

[(E1 - E0)/E0] * 100% = % change E

[(E1 - E0)/100] * 100% = % change E

E1 - E0 = change E

E1 = change E + E0 = .0044 + 100 = 100.0044

Originally, I got like 100.44. The professor said I was off by a factor of 10, i.e. E1 = 104.4.

willem2
Nov18-09, 05:20 PM
Your answer for #1 is already off by a factor of 10.

You calculation for #2 also has another error and it has the wrong sign.

for #3, only % \Delta E was asked. Amazingly enough,
the answer you got was actually correct even tough #1 and #2 were wrong

If you want further help, try to give a more detailed calculation.

Shackleford
Nov18-09, 06:19 PM
Your answer for #1 is already off by a factor of 10.

You calculation for #2 also has another error and it has the wrong sign.

for #3, only % \Delta E was asked. Amazingly enough,
the answer you got was actually correct even tough #1 and #2 were wrong

If you want further help, try to give a more detailed calculation.

Okay. I'm home now. Here's my work.

Refer first post.

willem2
Nov18-09, 06:27 PM
I see just a repeat of the question

Shackleford
Nov18-09, 06:28 PM
I see just a repeat of the question

You may have to clear the browser.

Shackleford
Nov18-09, 06:46 PM
I must be going crazy, because I don't see how I'm calculating #1 and #2 incorrectly!

willem2
Nov18-09, 06:55 PM
You may have to clear the browser.

it didn't help. You link to 2 jpeg files that contain parts of the question

Shackleford
Nov18-09, 06:58 PM
Try it again! I renamed them.

Shackleford
Nov18-09, 11:17 PM
No one? It's due tomorrow. :-/