An object moves uphill in a potential

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SUMMARY

An object moving "uphill" in a potential field experiences negative work done on it, resulting in a decrease in kinetic energy. This phenomenon is mathematically represented by the integral of the gradient of potential energy, specifically the equation -∫(1 to 2) ∇U · dr = -∫(1 to 2) dU. As the object ascends to a higher potential, it moves slower due to the energy transfer dynamics dictated by the potential energy landscape.

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an object moves "uphill" in a potential

[tex]=-\int_{1}^{2}\nabla\mbox{U}\cdot\mbox{dr}\[/tex]

[tex]=-\int_{1}^{2}\mbox{dU}[/tex]

How can this be?

Any help would be appreciated. Thank you
 
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This says, essentially, that if an object moves "uphill" in a potential, the work done on the object is negative and so it will have less kinetic energy (move slower) when it moves towards a higher potential.
 

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