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A proton moves .1m along hte direction of an electric field of magnitude 3V/m. what iss the change in kinetic energy of the proton?
I have KE = qE/d...1.6x10^-27 * 3V/m /(.1^2)= 4.8x 10^-25 but got it wrong on the test.
What did i do wrong?
Dx
Tom Mattson
Jul7-03, 07:58 PM
Originally posted by Dx
A proton moves .1m along hte direction of an electric field of magnitude 3V/m. what iss the change in kinetic energy of the proton?
I have KE = qE/d...
Note: In the formula, distance is not squared, which is correct.
1.6x10^-27 * 3V/m /(.1^2)= 4.8x 10^-25 but got it wrong on the test.
What did i do wrong?
You squared the distance, which is incorrect.
Darn it! I missed that on my test, stupid math mistakes gets me all the time. Thanks Tom!
Dx [;)]
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