I need the form of potential energy for a simple problem

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SUMMARY

The discussion focuses on deriving the potential energy function for a particle of mass "m" and charge "q" moving in a constant electric field "E" along an elliptical path. The Lagrangian function is established as L = T - U, where T represents the kinetic energy expressed as T = m/2*(X1² + X2²). The potential energy U is derived from the force F = qE, leading to the conclusion that U = -∫F dx, specifically in the direction of the electric field.

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  • Understanding of Lagrangian mechanics
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  • Knowledge of calculus for integration
  • Basic concepts of kinetic and potential energy
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  • Explore the relationship between force and potential energy in electric fields
  • Learn about the integration techniques for calculating potential energy
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Homework Statement



A particle of mass "m" and electric charge "q" moves without friction along an ellipse in the horizontal plane, in the presence of a constant electric field of intensity E directed along the large semiaxis of the ellipse.

Write the Lagrange function

Homework Equations



We now, obviously the ellipse equation so we choose as general coordinates:

X1 = a*cos(phi) X2 = b*sin(phi)

The Attempt at a Solution



L = T - U;

T = m/2*(X1'squared + X2' squared)

But U?
 
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We know that F=qE

How can we get U from F? (notice that there are no dissipative forces here)
 
Matterwave said:
We know that F=qE

How can we get U from F? (notice that there are no dissipative forces here)

Hehe. Yes. U = - integral (F - along x direction in our case - dx) because Fx = - dU/dx
 

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