Emissivity as a function of wavelength

[yellowputty]

1. The problem statement, all variables and given/known data

Hello, I'm a little confused. I did an experiment today with a Leslie Cube. One of the faces was a black paint, and another a white paint. I know that white reflects well and has a low emissivity, at least in the visual wavelengths. In the Leslie's cube, was hot water, so I was measuring the Irradiance of thermal radiation. From the results I concluded that the white and black faces had similar emissivities (in fact the white face was slightly higher). I understand that emissivity depends on several factors, temperature, angle and also wavelength. How come in the infrared spectrum, both faces have similar emissivities? I have a feeling the answer lies in a blackbody diagram. Can someone point me in the right direction?

Thanks in advance :)

[yellowputty]

I think I just worked it out. Colour has nothing to do with a materials ability to absorb and hence emit thermal radiation. Colour is important in reflecting and absorbing wavelengths in the visible spectrum only. A white material will reflect all visible wavelengths, but a black surface would absorb all, and re-emit as thermal radiation.

I think oberlooked the way that visible light is then turned into thermal radiation. Thank you!

[turin]

You may be correct. I thought of another problem. Maybe you are measuring reflected radiation that the cube reflects from external sources? How have you isolated this?